A) \[H{{e}^{+}}\]
B) \[x\,c{{m}^{-1}}\]
C) \[4x\,c{{m}^{-1}}\]
D) \[\frac{x}{4}\,c{{m}^{-1}}\]
Correct Answer: D
Solution :
\[C:H=\frac{85}{12}:\frac{15}{1}=1:2\] \[\therefore \] Empirical formula \[=C{{H}_{2}}\] Empirical formula weight \[=12+2\times 1=14\] Mol. wt. \[=2\times V.D.\] \[=2\times 28=56\] \[n=\frac{56}{14}=4\] Now, M.F. =n \[\times \] empirical formula \[=4\times C{{H}_{2}}\] \[={{C}_{4}}{{H}_{8}}\]
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