A) \[1.8mA\]
B) \[62V,\,\,2\Omega \]
C) \[63V,\,\,1\Omega \]
D) \[61V,\,\,1\Omega \]
Correct Answer: C
Solution :
Initial velocity of projectile, \[\text{4 }km/h\] At the two points of the trajectory during projection, the horizontal component of the velocity is the same. \[\text{5 }km/h\] \[{{10}^{-6}}{{m}^{2}}\] \[{{10}^{29}}\] Vertical component of \[250\times {{10}^{-3}}m/s\] \[25\times {{10}^{-3}}m/s\] Vertical component of \[2.50\times {{10}^{-3}}m/s\] \[1.25\times {{10}^{3}}m/s\] \[\frac{hv}{4}\] \[\frac{hv}{3}\] From the equation \[\frac{hv}{2}\] \[\frac{2hv}{3}\] \[30\mu A\] \[90\mu A\] \[=5.49s\]You need to login to perform this action.
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