A) \[25min\]
B) \[\frac{\omega M}{M+m}\]
C) \[\frac{\omega (M-2M)}{M+2m}\]
D) \[\frac{\omega (M-2M)}{M+2m}\]
Correct Answer: A
Solution :
Linear magnification \[m=\frac{l}{O}=\frac{f}{u-f}=\frac{10}{25-30}\] \[m=\frac{2}{3}\] Areal magnification \[={{m}^{2}}=\frac{4}{9}\] Area of image \[=\frac{4}{9}\times \] area of object \[=\frac{4}{9}\times {{(3)}^{2}}=4c{{m}^{2}}\]You need to login to perform this action.
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