A) ethoxy ethane
B) 1-butanol
C) 1-methoxy propane
D) 2-methoxy propane
Correct Answer: A
Solution :
\[{{C}_{4}}{{H}_{10}}O\xrightarrow{Hl}\] only one type of halide. Therefore, \[{{C}_{4}}{{H}_{10}}O\] may be a symmetrical ether. i.e.,. ethoxy ethane.You need to login to perform this action.
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