A) \[{{E}_{I}}={{E}_{II}}={{E}_{III}}\,and\,\,\,{{E}_{IV}}>{{E}_{V}}\]
B) \[\frac{Mgx}{4}\]
C) \[Mgx\]
D) \[\frac{Mgx}{2}\]
Correct Answer: D
Solution :
It is clear from the adjacent diagram \[{{v}_{p}}=v-\omega t=0\] \[\Rightarrow \] \[v=\omega r\] Again \[{{v}_{Q}}=v+\omega t\] \[=\omega t+\omega r=v+v=2v\]You need to login to perform this action.
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