A) \[\frac{2\eta }{\lambda }[1-{{e}^{-\lambda t}}]\]
B) \[\frac{\eta }{2\lambda }[1-{{e}^{-\lambda t}}]\]
C) \[\frac{\eta }{{{\lambda }^{2}}}[1-{{e}^{-{{\lambda }^{2}}t}}]\]
D) \[\frac{\eta }{\lambda }[1-{{e}^{-\lambda t}}]\]
Correct Answer: C
Solution :
(c.)Balancing forces we can write \[\frac{2G\lambda m}{{{a}^{2}}}=\frac{m{{v}^{2}}}{a}\] \[\Rightarrow \] \[v=\sqrt{2\lambda G}\] Thus, time period \[T=\frac{2\pi a}{v}=2\pi \sqrt{\frac{{{a}^{2}}}{2G\lambda }}\]You need to login to perform this action.
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