A) \[\frac{2{{\eta }^{2}}}{g{{a}^{2}}}\]
B) zero
C) \[\frac{{{\eta }^{2}}}{g{{a}^{2}}}\]
D) \[\frac{{{\eta }^{2}}}{2g{{a}^{2}}}\]
Correct Answer: D
Solution :
Consider an elementary portion of the ring. Electric field at the centre due this elementary portion is \[{{v}_{P}}=v,\,\,{{v}_{Q}}=0\]You need to login to perform this action.
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