A) \[0.1M\]
B) \[N{{H}_{4}}Cl\]
C) \[100mL\]
D) \[0.2M\]
Correct Answer: B
Solution :
\[{{p}_{C}}=\frac{a}{27{{b}^{2}}}\] basic character decreases down the group. \[=\frac{6.5}{27\times {{(0.056)}^{2}}}=76.8\,atm\] \[=\frac{6.5}{27\times {{(0.056)}^{2}}}=76.8\,atm\] \[a/d{{m}^{6}}\,bar\,mo{{l}^{-2}}\] It means \[b/d{{m}^{6}}\,mo{{l}^{-2}}\] is most basic. As we known that more the basic compound, more is the pH [pH oc basic character]. Thus, \[6.5\]
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