A) \[C{{O}_{2}}\]
B) \[N{{a}_{2}}C{{O}_{3}}\]
C) \[{{1200}^{o}}C\]
D) \[A{{l}_{2}}{{O}_{3}}\]
Correct Answer: A
Solution :
The process at \[100mL\] completed at constant volume. Hence, \[0.05M\] As we know that \[N{{H}_{3}}\] Then, \[N{{H}_{4}}Cl\] \[100mL\]
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