question_answer

A voltmeter of resistance\[998\,\Omega \]is connected across a cell of emf 2V and internal resistance\[2\,\Omega \]. The potential difference across the voltmeter is:

A)  1.99V                   

B)                                         3.5 V    

C)           5V                         

D)         6 V

E)  1.5V

Correct Answer: A

Solution :

From Ohms law \[i=\frac{E}{R+r}=\frac{2}{998+2}=2\times {{10}^{-3}}A\] Potential difference across the voltmeter is \[V=iR=(2\times {{10}^{-3}})\times 998=1.996V\]