A) 94, 230
B) 232, 90
C) 190, 32
D) 230, 94
E) none of the above
Correct Answer: B
Solution :
The decay equation is \[_{92}{{X}^{A}}{{\xrightarrow{{}}}_{z}}{{Y}^{228}}+\alpha \] \[\alpha -\]particle is nucleus of \[_{2}H{{e}^{4}}\] \[_{92}{{X}^{A}}{{\xrightarrow[{}]{{}}}_{Z}}{{Y}^{228}}{{+}_{2}}H{{e}^{4}}\] \[\therefore \] \[A=228+4=232\] \[Z=92-2=90\]You need to login to perform this action.
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