A) 3
B) 2
C) 4
D) 5
E) 1
Correct Answer: A
Solution :
\[{{C}_{2}}{{H}_{12}}\]has three isomers. \[\underset{n-pentane}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}C{{H}_{3}}}}\,\] \[\underset{neo-pentane}{\mathop{C{{H}_{3}}-\underset{\begin{smallmatrix} | \\ C{{H}_{3}} \end{smallmatrix}}{\overset{\begin{smallmatrix} C{{H}_{3}} \\ | \end{smallmatrix}}{\mathop{C}}}\,-C{{H}_{3}}}}\,\]You need to login to perform this action.
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