CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    In the adjoining circuit, the resistance are given in ohms X and Y are unknown resistances. The current through the 100 resistance is 3A, while that through the resistance X is 1A. No current passes through the galvanometer. The values of the unknown resistance X and Y are. respectively:

    A)  \[12\,\Omega \]and\[12\,\Omega \] 

    B)        \[12\,\Omega \] and\[6\,\Omega \]

    C)                        \[6\,\Omega \]and\[12\,\Omega \]

    D)        \[6\,\Omega \]and\[6\,\Omega \]

    E)  \[14\,\Omega \]and \[54\,\Omega \]

    Correct Answer: D

    Solution :

    When no current passes through the galvanometer, the bridge is balanced hence,                 \[\frac{P}{Q}=\frac{R}{S}\] \[\Rightarrow \]               \[\frac{24+X}{10}=\frac{84+Y}{30}\] Also, applying Kirchhoffs law \[\Sigma iR=\Sigma iR\]           (parallel) \[(X+24)+(84)+Y=(10+30)\] \[\Rightarrow \]               \[X+Y=12\]                       ...(1) and        \[3X-Y=12\]                       ...(2) From Eqs. (l)and (2), we get \[X=6,\text{ }Y=6\](neglecting negative value)


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