A) \[0.3\times {{10}^{4}}yr\]
B) \[0.3\times {{10}^{3}}yr\]
C) \[0.3\times {{10}^{8}}yr\]
D) \[0.3\times {{10}^{2}}yr\]
E) \[0.3\times {{10}^{-4}}yr\]
Correct Answer: A
Solution :
\[\because \] \[{{t}_{1/2}}=\frac{0.693}{k}\] \[=\frac{0.693}{2.31\times {{10}^{-4}}}=0.3\times {{10}^{4}}yr\]
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