A) 27cal
B) 54 cal
C) 300 cal
D) 600 cal
E) none of these
Correct Answer: C
Solution :
\[CO(g)+\frac{1}{2}{{O}_{2}}(g)\xrightarrow{{}}C{{O}_{2}}(g)\] \[\because \] \[{{q}_{p}}={{q}_{v}}+\Delta nRT\] \[\Delta n=1-1\frac{1}{2}=-\frac{1}{2}\] \[R=2\,cal\] \[T=300\,K\] \[\therefore \] \[{{q}_{p}}={{q}_{v}}+\left( -\frac{1}{2} \right)(2)(300)\] \[{{q}_{p}}={{q}_{v}}-300\] \[{{q}_{p}}-{{q}_{v}}=300\,cal\]
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