A) 900 W
B) 450 W
C) 300 W
D) 200 W
E) 100 W
Correct Answer: D
Solution :
Let\[{{R}_{1}}\]and\[{{R}_{2}}\]be the resistances, then \[H=\frac{{{V}^{2}}}{R}\] \[\therefore \] \[{{R}_{1}}=\frac{{{(200)}^{2}}}{300},{{R}_{2}}=\frac{{{(200)}^{2}}}{600}\] In series, \[R={{R}_{1}}+{{R}_{2}}=\frac{{{(200)}^{2}}}{300}+\frac{{{(200)}^{2}}}{600}\] \[=\frac{{{(200)}^{2}}}{100}\left[ \frac{1}{3}+\frac{1}{6} \right]\] \[=200\,\Omega \] Heat output, \[H=\frac{{{V}^{2}}}{R}=\frac{{{(200)}^{2}}}{200}=200\,V\]You need to login to perform this action.
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