A) 0.25 N
B) 1 N
C) 2N
D) 7 N
E) 5N
Correct Answer: B
Solution :
Molarity of\[{{H}_{2}}S{{O}_{4}}=5M\] Normality of \[{{H}_{2}}S{{O}_{4}}=2\times 5=10N\] \[\because \] \[{{N}_{1}}{{V}_{1}}={{N}_{2}}{{V}_{2}}\] \[10\times 1={{N}_{2}}\times 10\] \[{{N}_{2}}=1N\]
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