CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    The point, which is equidistant from the points (0, 0, 0), (2, 0, 0), (0, 2, 0) and (2, 2, 2) is:

    A)  \[(1,0,1)\]         

    B)         (0, 1, 1)

    C)  \[(1,1,-1)\]        

    D)         (1, 1, 0)

    E)  (1, 1, 1)

    Correct Answer: E

    Solution :

    Let the point be \[(x,y,z)\]                 \[\Rightarrow \,\,{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{(x-2)}^{2}}\,+{{y}^{2}}+{{z}^{2}},\] \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{x}^{2}}+{{(y-2)}^{2}}+{{z}^{2}}\] and        \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}={{(x-2)}^{2}}\]                                                 \[+{{(y-2)}^{2}}+{{(z-2)}^{2}}\] Point (1, 1, 1) satisfies all the above equations.


You need to login to perform this action.
You will be redirected in 3 sec spinner