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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    \[\left( \frac{d}{dx} \right)[\log (\sec x-\tan x)]\]is equal to:

    A)  \[-sec\text{ }x\]             

    B)  \[sec\text{ }x+tan\text{ }x\]

    C)  \[sec\text{ }x\]               

    D)         \[sec\text{ }x-tan\text{ }x\]

    E)  \[tan\text{ }x-sec\text{ }x\]

    Correct Answer: A

    Solution :

    \[\frac{d}{dx}[\log (\sec x-\tan x)]\] \[=\frac{1}{\sec x-\tan x}[\sec x\tan x-{{\sec }^{2}}x]\] \[=\frac{\sec x[\tan x-\sec x]}{\sec x-\tan x}=-\sec x\]


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