A) 6, 9
B) 9, 12
C) 3, 6
D) 4, 8
E) 1, 13
Correct Answer: C
Solution :
Let the numbers a, b \[\therefore \] \[\frac{a+b}{2ab}=\frac{1}{4}\Rightarrow \frac{2ab}{a+b}=4\] and \[\frac{a+b}{2}=A,\sqrt{ab}=G\] \[\therefore \] \[2A+{{G}^{2}}=a+b+ab=27\] also \[2(a+b)-ab=0\] \[\Rightarrow \]\[a=3,\text{ }b=6\]will satisfy the given equation.You need to login to perform this action.
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