A) \[-sec\text{ }x\]
B) \[sec\text{ }x+tan\text{ }x\]
C) \[sec\text{ }x\]
D) \[sec\text{ }x-tan\text{ }x\]
E) \[tan\text{ }x-sec\text{ }x\]
Correct Answer: A
Solution :
\[\frac{d}{dx}[\log (\sec x-\tan x)]\] \[=\frac{1}{\sec x-\tan x}[\sec x\tan x-{{\sec }^{2}}x]\] \[=\frac{\sec x[\tan x-\sec x]}{\sec x-\tan x}=-\sec x\]You need to login to perform this action.
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