A) (8, 41)
B) \[(-8,41)\]
C) (41, 8)
D) \[(-41,8)\]
E) \[(-8,-41)\]
Correct Answer: B
Solution :
If\[4-5i\]is root of\[{{x}^{2}}+ax+b=0,\]then\[4+5i\]is also the root. \[\therefore \] Sum of roots\[=-a=8\] \[\Rightarrow \] \[a=-8\] and product of roots \[=16+25=b=41\] \[\therefore \] \[(a,b)=(-8,41)\]You need to login to perform this action.
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