A) (1, 1)
B) \[(1,-1)\]
C) \[(-1,1)\]
D) (0, 1)
E) (0, 1)
Correct Answer: A
Solution :
Slope of line\[x+y=0\]is\[-1,\]therefore slope of required tangent\[=-1\] Given curve is\[2y=3-{{x}^{2}}\Rightarrow 2\frac{dy}{dx}=-2x\] \[\Rightarrow \] \[\frac{dy}{dx}=-x=-1\] \[\Rightarrow \] \[x=1\] and \[2y=3-1\Rightarrow y=1\] \[\therefore \] Required point is (1, 1).You need to login to perform this action.
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