A) (1, 2)
B) \[(-1,2)\]
C) \[(1,-2)\]
D) \[\left( \frac{1}{4},2 \right)\]
E) \[\left( -\frac{1}{4},2 \right)\]
Correct Answer: D
Solution :
\[{{y}^{2}}=5x+4y+1\] \[\Rightarrow \] \[{{y}^{2}}-4y+4=5x+1+4\] \[\Rightarrow \] \[{{(y-2)}^{2}}=5(x+1)\] Let \[y-2=Y\] and \[x+1=X\] \[\Rightarrow \] \[{{Y}^{2}}=5X\] Here \[a=\frac{5}{4}\] \[\therefore \] Focus is \[(X=a,\text{ }Y=0)\] i.e., \[\left( x=\frac{5}{4}-1,y=2 \right)\] \[\Rightarrow \] focus\[=\left( \frac{1}{4},2 \right)\]You need to login to perform this action.
You will be redirected in
3 sec