A) \[\frac{1}{2}\]
B) \[2\]
C) \[1\]
D) \[\frac{1}{3}\]
E) \[\frac{1}{5}\]
Correct Answer: A
Solution :
\[\therefore \] \[4{{\sin }^{-1}}(x)+{{\cos }^{-1}}x=\pi \] \[\Rightarrow \] \[4{{\sin }^{-1}}x+\frac{\pi }{2}-{{\sin }^{-1}}x=\pi \] \[\Rightarrow \] \[3{{\sin }^{-1}}x=\frac{\pi }{2}\] \[\Rightarrow \] \[x=\sin \left( \frac{\pi }{6} \right)=\frac{1}{2}\]You need to login to perform this action.
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