A) 2 sq unit
B) 1 sq unit
C) 4 sq unit
D) 3 sq unit
E) 6 sq unit
Correct Answer: D
Solution :
Required area\[=\int_{6}^{9}{\frac{36}{{{x}^{2}}}}dx=\left[ -\frac{36}{x} \right]_{6}^{9}\] \[=-36\left[ \frac{1}{9}-\frac{1}{6} \right]=3\,sq.\,unit\]You need to login to perform this action.
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