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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    The HM of 2 numbers is 4. Their AM is A and GM is G. If G satisfies\[2A+{{G}^{2}}=27,\]the numbers are:

    A)  6, 9    

    B)                                         9, 12                     

    C)         3, 6                                       

    D)         4, 8

    E)         1, 13

    Correct Answer: C

    Solution :

    Let the numbers a, b \[\therefore \]  \[\frac{a+b}{2ab}=\frac{1}{4}\Rightarrow \frac{2ab}{a+b}=4\] and        \[\frac{a+b}{2}=A,\sqrt{ab}=G\] \[\therefore \]  \[2A+{{G}^{2}}=a+b+ab=27\] also       \[2(a+b)-ab=0\] \[\Rightarrow \]\[a=3,\text{ }b=6\]will satisfy the given equation.


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