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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2000

  • question_answer
    The photoelectric cut-off voltage in an experiment was found to be 1.5 V. The work function for the material used in the experiment was 4.2 eV. The maximum kinetic energy of the photoelectrons that was emitted was:

    A)  1.5 eV                 

    B)         2.7 eV

    C)  4.2 eV                 

    D)         5.7 eV

    E)  none of the above

    Correct Answer: A

    Solution :

    If stopping potential is\[{{V}_{0}},\]then maximum kinetic energy of photoelectrons is given by \[Ek=eV\] Given,                   V= 1.5 volt \[\therefore \]                  \[{{E}_{k}}=1.5eV\]


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