A) 43 g
B) 86 g
C) 129 g
D) 172 g
E) 22 g
Correct Answer: B
Solution :
\[%\]of \[C=\frac{12}{44}\times \frac{2.63}{0.858}\times 100=83.5%\] \[%\]if\[H=\frac{2}{18}\times \frac{1.28}{0.858}\times 100=16.5%\]Element | % | Relative no. of atoms | Simplest ration |
C | 83.5 | 83.5/12=7 | 7/7=1 |
H | 16.5 | 16.5/1=16.5 | 16.5/1 =2.35 |
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