A) \[{{E}_{1}}={{E}_{2}}\]
B) \[{{E}_{2}}=0\ne {{E}_{1}}\]
C) \[{{E}_{1}}>{{E}_{2}}\]
D) \[{{E}_{1}}<{{E}_{2}}\]
E) none of these
Correct Answer: C
Solution :
\[{{E}_{2}}={{E}_{1}}-\frac{0.0591}{n}\log \frac{[Z{{n}^{2+}}]}{[C{{u}^{2+}}]}\] \[{{E}_{2}}={{E}_{1}}-\frac{0.0591}{2}\log \frac{1}{0.01}\] \[{{E}_{2}}={{E}_{1}}-0.0591\] Hence, \[{{E}_{1}}>{{E}_{2}}\]You need to login to perform this action.
You will be redirected in
3 sec