A) \[1.2\times {{10}^{4}}cal\]
B) \[2.4\times {{10}^{4}}cal\]
C) \[6.0\times {{10}^{4}}cal\]
D) \[4.8\times {{10}^{4}}cal\]
E) \[3.6\times {{10}^{4}}cal\]
Correct Answer: A
Solution :
As \[\frac{{{Q}_{2}}}{{{Q}_{1}}}=\frac{{{T}_{2}}}{{{T}_{1}}}\] \[\therefore \] \[\frac{{{Q}_{2}}}{6\times {{10}^{4}}}=\frac{127+273}{227+273}=\frac{400}{500}\] \[\therefore \] \[{{Q}_{2}}=\frac{4}{5}\times 6\times {{10}^{4}}=4.8\times {{10}^{4}}cal\] \[\therefore \] \[W={{Q}_{1}}-{{Q}_{2}}=6\times {{10}^{4}}-4.8\times {{10}^{4}}\] \[=1.2\times {{10}^{4}}\,cal\]
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