A) 9.0 cm
B) 7.5 cm
C) 6.0 cm
D) 3.0cm
E) 1.5 cm
Correct Answer: D
Solution :
Height to which water rises in the capillary tube is \[h=\frac{2T\cos \theta }{r\rho g}\] Given,\[T=75\text{ }dyne/cm,\text{ }\theta =0{}^\circ ,\text{ }r=\frac{1}{2}\times 10\text{ }cm.\] \[g=10\text{ }m/{{s}^{2}},\text{ }\rho =1\text{ }g/cc.\] \[\therefore \] \[h=\frac{2\times 75\times \cos 0{}^\circ \times 2}{10\times 10}=3cm\]You need to login to perform this action.
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