A) ammoniacal silver nitrate solution
B) neutral ferric chloride solution
C) sodium hydroxide solution
D) sodium carbonate solution
E) phenolphthalein
Correct Answer: A
Solution :
Formic acid (methanoic acid) can reduce ammoniacal silver nitrate (Tollens reagent) to silver mirror because it acts as reducing agent and in it H-atom linked with\[-COOH\]group is easily oxidized to\[-OH\]group, as follows: \[HCOOH+A{{g}_{2}}O\xrightarrow[{}]{amm.\,AgN{{O}_{3}}}{{H}_{2}}O\] \[+C{{O}_{2}}+\underset{\begin{smallmatrix} silver \\ mirror \end{smallmatrix}}{\mathop{2Ag\downarrow }}\,\] While acetic acid (ethanoic acid) cannot react with ammoniacal silver nitrate solution.
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