A) + 1 to + 3
B) + 2 to + 4
C) + 3 to + 5
D) + 4 to + 6
E) + 5 to + 7
Correct Answer: D
Solution :
In the proportion of potassium permanganate \[Mn{{O}_{2}}\]converted to\[{{K}_{2}}Mn{{O}_{4}}\] In\[Mn{{O}_{2}}\]oxidation state of\[Mn\]is, \[x+(2\times -2)=0\] \[x-4=0\] \[x=+\text{ }4\] In \[{{K}_{2}}Mn{{O}_{4}}\]oxidation state of\[Mn\]is, \[2+x+(4x-2)=0\] \[2+x+(-8)=0\] \[x-6=0\] \[x=+\text{ }6\] It means that oxidation state of\[Mn\]changes from +4 to+6.
You need to login to perform this action.
You will be redirected in
3 sec
