A) 10 kg
B) 0.98 kg
C) 5kg
D) 20 kg
E) 4kg
Correct Answer: B
Solution :
\[k=\frac{F}{l}=\frac{10\times g}{0.25}=40\,g\,N/m\] \[T=2\pi \sqrt{\left( \frac{m}{k} \right)}\Rightarrow {{T}^{2}}=\frac{4{{\pi }^{2}}m}{k}\] \[\Rightarrow \] \[{{\left( \frac{\pi }{10} \right)}^{2}}=\frac{4{{\pi }^{2}}m}{40g}\] \[\therefore \] \[m=0.98kg\]You need to login to perform this action.
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