A) 1
B) 2
C) 3
D) 4
E) none of these
Correct Answer: C
Solution :
The centre and radius of circle\[{{x}^{2}}+{{y}^{2}}=4\]are \[{{C}_{1}}(0,\text{ }0)\]and\[{{r}_{1}}=2\]respectively and the centre and radius of circle\[{{x}^{2}}+{{y}^{2}}-8x+12=0\]are \[(4,0)\]and\[{{r}_{2}}=2\]. \[\because \] \[{{C}_{1}}{{C}_{2}}={{r}_{1}}+{{r}_{2}}\] \[\therefore \]Circles touch each other externally, therefore number of common tangents are 3.You need to login to perform this action.
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