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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The equation of the chord of the parabola \[{{y}^{2}}=8x\]which is bisected at the point\[(2,-3),\]is:

    A) \[4x+3y+1=0\]

    B)         \[3x+4y-1=0\]

    C)  \[4x-3y-1=0\]

    D)         \[3x-4y+1=0\]

    E)  \[4x+3y=0\]

    Correct Answer: A

    Solution :

    The equation of the chord of the parabola \[{{y}^{2}}=8x\]which is bisected at\[(2,-3),\]is \[y(-3)-4(x+2)=(-3)-8\times 2\] \[\Rightarrow \]               \[-3y-4x-8=9-16\] \[\Rightarrow \]               \[4x+3y+1=0\]


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