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  3. CEE Kerala Engineering

CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    If\[x+y+1=0\]touches the parabola\[{{y}^{2}}=\lambda x,\] then K is equal to:

    A)  2                                            

    B)  4

    C)  6                            

    D)         8

    E)  none of these

    Correct Answer: B

    Solution :

    \[\because \]\[x+y+1=0\]touches the parabola\[{{y}^{2}}=\lambda x,\]then \[-1=\frac{\lambda /4}{-1}\]                       \[\left[ \because C=\frac{a}{m} \right]\] \[\Rightarrow \]               \[\frac{\lambda }{4}=1\] \[\Rightarrow \]               \[\lambda =4\]


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