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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The sum of the distances of any point on the ellipse\[3{{x}^{2}}+4{{y}^{2}}=24\]from its foci, is:

    A)  \[8\sqrt{2}\]                                     

    B)  8

    C)  \[16\sqrt{2}\]                  

    D)         \[2\sqrt{2}\]

    E)  \[4\sqrt{2}\]

    Correct Answer: E

    Solution :

    Equation of ellipse is \[3{{x}^{2}}+4{{y}^{2}}=24\] \[\Rightarrow \]               \[\frac{{{x}^{2}}}{8}+\frac{{{y}^{2}}}{6}=1\] Here \[a=2\sqrt{2}\]and\[b=\sqrt{6}\]. The sum of the distances of any point on the ellipse from its foci is\[2a=4\sqrt{2}\].


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