CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    The value of\[sin\text{ }12{}^\circ \text{ }sin\text{ }48{}^\circ \text{ }sin\text{ }54{}^\circ \]is equal to:

    A)  \[\frac{2}{3}\]                                  

    B)  \[\frac{1}{2}\]

    C)  \[\frac{1}{8}\]                  

    D)         \[\frac{1}{3}\]

    E)  3

    Correct Answer: C

    Solution :

    \[sin\text{ }12{}^\circ \text{ }sin\text{ }48{}^\circ \text{ }sin\text{ }54{}^\circ \] \[=\frac{1}{2}[\cos 36{}^\circ -\cos 60{}^\circ ]\sin 54{}^\circ \] \[=\frac{1}{2}\left[ \frac{\sqrt{5}+1}{4}-\frac{1}{2} \right]\left[ \frac{\sqrt{5}+1}{4} \right]\] \[=\frac{1}{2}\left[ \frac{\sqrt{5}-1}{4} \right]\left[ \frac{\sqrt{5}+1}{4} \right]=\frac{5-1}{2\times 4\times 4}\] \[=\frac{1}{8}\]


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