A) \[\frac{1}{13}\]
B) \[\frac{1}{13}\times \frac{1}{17}\]
C) \[\frac{1}{52}\times \frac{1}{51}\]
D) \[\frac{1}{13}\times \frac{4}{51}\]
E) \[\frac{1}{13}\times \frac{1}{13}\]
Correct Answer: E
Solution :
Two cards are drawn successively with replacement from a well-shuffled pack of 52 cards. The probability of drawing two aces \[=\frac{4}{52}\times \frac{4}{52}=\frac{1}{13}\times \frac{1}{13}\]
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