A) 1
B) 2
C) 3
D) 4
E) none of these
Correct Answer: C
Solution :
\[\because \]\[f(x)=\frac{x+1}{x-1}\] \[\therefore \] \[f(2)=\frac{2+1}{2-1}=3\] \[f\{f(2)\}=f(3)=\frac{3+1}{3-1}=\frac{4}{2}=2\] and \[f[f\{f(2)\}]=f(2)=\frac{2+1}{2-1}=3\]You need to login to perform this action.
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