A) \[40{}^\circ \]
B) \[\frac{45{}^\circ }{2}\]
C) \[60{}^\circ \]
D) \[30{}^\circ \]
E) \[90{}^\circ \]
Correct Answer: D
Solution :
Let BC = h, then \[AB=\sqrt{3}h\] In \[\Delta ABC\] \[\tan \theta =\frac{BC}{AB}=\frac{h}{\sqrt{3}h}\] \[\Rightarrow \] \[\tan \theta =\frac{1}{\sqrt{3}}=\tan 30{}^\circ \] \[\Rightarrow \] \[\theta =30{}^\circ \]You need to login to perform this action.
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