CEE Kerala Engineering
CEE Kerala Engineering Solved Paper-2001
question_answer
A uniform wire of resistance\[9\,\Omega \]is cut into equal parts. They are connected in the form of equilateral triangle ABC. A cell of emf 2 V and negligible internal resistance is connected across B and C. Potential difference across AB is:
A) 1 V
B) 2 V
C) 3 V
D) 0.5 V
E) 0.25 V
Correct Answer:
C
Solution :
\[R=\frac{9}{3}=3\,\Omega \] \[{{R}_{net}}=2\,\Omega \] PD across AB \[V=i\times R=\frac{V}{{{R}_{net}}}\times R\] \[=\frac{2}{2}\times 3=3V\]