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CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    In a potentiometer experiment two cells of emf\[{{E}_{1}}\]and\[{{E}_{2}}\]are used in series and in conjunction and the balancing length is found to be 58 cm of the wire. If the polarity of\[{{E}_{2}}\]is reversed, then the balancing length becomes 29 cm. The ratio\[{{E}_{1}}/{{E}_{2}}\]of the emfs of the two cells is:

    A)  \[1:1\]                                 

    B) \[2:1\]                  

    C)  \[3:1\]                 

    D)        \[4:1\]

    E)  \[1:2\]

    Correct Answer: C

    Solution :

    \[{{E}_{1}}+{{E}_{2}}=k\times 58\]                                      ...(1) \[{{E}_{1}}-{{E}_{2}}=k\times 29\]                                      ...(2) \[\therefore \]  \[\frac{{{E}_{1}}+{{E}_{2}}}{{{E}_{1}}-{{E}_{2}}}=2\] \[\Rightarrow \]               \[\frac{{{E}_{1}}}{{{E}_{2}}}=\frac{3}{1}\]


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