CEE Kerala Engineering CEE Kerala Engineering Solved Paper-2001

  • question_answer
    If\[\overrightarrow{x}\]and\[\overrightarrow{y}\]are two unit vectors and\[\theta \]is the angle between them, then \[|\vec{x}-\vec{y}|\] is equal to:

    A)  \[2\sin \left( \frac{\theta }{2} \right)\] 

    B)         \[2\cos \left( \frac{\theta }{2} \right)\]

    C)  \[\sin \left( \frac{\theta }{2} \right)\]    

    D)         \[\cos \left( \frac{\theta }{2} \right)\]

    E)  \[\left( \frac{\theta }{2} \right)\]

    Correct Answer: A

    Solution :

    \[|\overrightarrow{x}-\overrightarrow{y}{{|}^{2}}={{\overrightarrow{x}}^{2}}+{{\overrightarrow{y}}^{2}}-2\overrightarrow{x}.\overrightarrow{y}\] \[=1+1-2\cos \theta \]                 \[=2(1-\cos \theta )=2.2{{\sin }^{2}}\left( \frac{\theta }{2} \right)\] \[\Rightarrow \]               \[|\overrightarrow{x}-\overrightarrow{y}{{|}^{2}}=4{{\sin }^{2}}\left( \frac{\theta }{2} \right)\] \[\Rightarrow \]               \[|\overrightarrow{x}-\overrightarrow{y}|=2\sin \left( \frac{\theta }{2} \right)\]


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