A) 10
B) 24
C) 40
D) 36
E) 20
Correct Answer: A
Solution :
\[\because \]\[|\overrightarrow{a}-\overrightarrow{b}{{|}^{2}}={{\overrightarrow{a}}^{2}}+{{\overrightarrow{b}}^{2}}-2\overrightarrow{a}.\overrightarrow{b}\] \[\Rightarrow \] \[100=36+64-2\overrightarrow{a}.\overrightarrow{b}\] \[\Rightarrow \] \[\overrightarrow{a}.\overrightarrow{b}=0\] \[\therefore \] \[|\overrightarrow{a}+\overrightarrow{b}{{|}^{2}}={{\overrightarrow{a}}^{2}}+{{\overrightarrow{b}}^{2}}+2\overrightarrow{a}.\overrightarrow{b}\] \[=36+64+0=100\] \[\Rightarrow \] \[|\overrightarrow{a}+\overrightarrow{b}|=10\]
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