A) \[\sin \alpha \]
B) \[\cos \alpha \]
C) \[\sin \beta \]
D) \[\cos 2\beta \]
E) \[\sin 2\alpha \]
Correct Answer: C
Solution :
\[\because \] \[cot(\alpha +\beta )=0\] \[\Rightarrow \] \[\cot (\alpha +\beta )=\cot 0{}^\circ \] \[\Rightarrow \] \[\alpha +\beta =0{}^\circ \] \[\therefore \,\,\,\,\,\,\,\,\,\sin (\alpha +2\beta )\,=\sin (\alpha +\beta +\beta )\] \[=\sin \beta \]You need to login to perform this action.
You will be redirected in
3 sec