A) \[\frac{1}{7}\]
B) \[\frac{2}{7}\]
C) \[\frac{3}{7}\]
D) \[\frac{4}{7}\]
E) \[\frac{1}{53}\]
Correct Answer: C
Solution :
In a non-leap year the probability of getting 53 Sundays or 53 Tuesdays or 53 Thursdays\[=\frac{1}{7}+\frac{1}{7}+\frac{1}{7}=\frac{3}{7}.\]You need to login to perform this action.
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