A) \[0<t<\frac{2}{3}\]
B) \[0<t<1\]
C) \[0<t<\frac{3}{2}\]
D) \[\frac{1}{2}<t<1\]
E) \[1<t<\frac{3}{2}\]
Correct Answer: C
Solution :
For the particle to be on the negative half of the axis \[x<0\] \[\therefore \] \[2{{t}^{3}}-3{{t}^{2}}<0\] \[\Rightarrow \] \[{{t}^{2}}(2t-3)<0\] \[\Rightarrow \] \[t>0,t<\frac{3}{2}\] (\[\because \]time cannot be negative) \[\therefore \] \[0<t<\frac{3}{2}\]You need to login to perform this action.
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